find the perimeter of a rectangle whose adjacent sides are x-3y+5z amd 3x-5y-2z
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Answered by
1
Answer:
solution
Step-by-step explanation:
Perimeter of a rectangle is 2(L+B)
Given, two adjacent sides are 5x
2
+2xy−13,2x
2
−6xy+11
Therefore,
2(L+B)
=2(5x
2
+2xy−13+2x
2
−6xy+11)
=2(7x
2
−4xy−2)
=14x
2
−8xy−4
Answered by
6
Answer:
Length=3x-5y-4z and Breadth=x-3y+5z.... Therefore, the perimeter of the rectangle is 8x-16y+2z.
Step-by-step explanation:
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