find the perimeter of a rectangle whose area is 600 cm square and breadth is 25 cm
Answers
Answered by
13
Let the length be x
Breadth = 25 cm
So,
Length * breath = area of rectangle
X * 25 = 600
25x = 600
X = 600/25
X = 24
So,
Length = 24 cm
Breadth = 25 cm
Therefore, perimeter = 2 ( l + b)
= 2( 24 + 25)
= 2 * 49
= 98 cm
Hope it helps...!!!
Breadth = 25 cm
So,
Length * breath = area of rectangle
X * 25 = 600
25x = 600
X = 600/25
X = 24
So,
Length = 24 cm
Breadth = 25 cm
Therefore, perimeter = 2 ( l + b)
= 2( 24 + 25)
= 2 * 49
= 98 cm
Hope it helps...!!!
ramanjyot:
thank you so much
Answered by
1
Answer:
Perimeter of the rectangle is 98 cm
Step-by-step explanation:
It is given that the area of the rectangle is 600 cm^2 and breadth of the rectangle is 25 cm.
And, from the properties of rectangle we know that area of rectangle remains equal to the product of its length and breadth.
Thus,
= > 600 cm^2 = 25 cm x length
= > 600 m^2 =25 cm x length
= > 600 m^2 / 25 m = length
= > 24 m = length
Therefore,
Perimeter of the rectangle = 2( length + breadth )
= 2( 24 cm + 25 cm )
= 2 ( 49 cm )
= 98 cm
Hence,
Perimeter of the rectangle is 98 cm.
Similar questions