plzz solve 9th and 12th question fastly it's urgent......i would be very thankful to you
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I can give the and of qus 12 acc to qus let the h be x
so it's l be 3x and b be 3\2 x. now it's at will be 216÷1.50 it will give 144 sq m
now ar of four walls is 144
2(l+b)h=144
by l=3x,b=3\2x,h=x we can get x= 4
so it's l be 3x and b be 3\2 x. now it's at will be 216÷1.50 it will give 144 sq m
now ar of four walls is 144
2(l+b)h=144
by l=3x,b=3\2x,h=x we can get x= 4
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pcm with hindi
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physics chemistry and maths
are u asking me after 12
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we have to find the area of all the sides and add it
or else if u know TSA its good
or else if u know TSA its good
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it's answer is 4520
okay
hmm
now can u solve ???
can u send me solution
I don't know how to solve sister
just answer is given
that's 4520 cm^2
One side of the cubiodal box is open, so u have to leave that area. Area of cardboard required =LSA of box(cuboid)+area of the base=2h(l+b)+50*28=2(20)(50+28)+1400=40*78+1400=3120+1400=4520cm.sq
thnx
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