find the perimeter of a rectangle whose area is 600 CM square and breadth is 25 CM
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Answered by
4
Hey!
Area= 600cm^2
Breadth= 25 cm
Let length = x
Area of rectangle= Length×Breadth
600=x*25
600/25=x
x= 24cm
Length= 24cm
Perimeter of rectangle= 2(l+b)
= 2(24+25)
=98 cm
Hope it helps...!!!
Area= 600cm^2
Breadth= 25 cm
Let length = x
Area of rectangle= Length×Breadth
600=x*25
600/25=x
x= 24cm
Length= 24cm
Perimeter of rectangle= 2(l+b)
= 2(24+25)
=98 cm
Hope it helps...!!!
Answered by
2
hey mate!!!!.
given=>
in a rectangle
breadth= 25cm
area = 600cm^2
to find =>
perimeter of rectangle
solution=>
area of rectangle = length×breadth
600 = l× 25
600/25 = length
24 cm = length
now ,
perimeter of rectangle= 2(l+b)
= 2( 24+25)
= 2(49).
= 98cm..
thus , perimeter of rectangle is 98 cm.
hope this helps!!!!
given=>
in a rectangle
breadth= 25cm
area = 600cm^2
to find =>
perimeter of rectangle
solution=>
area of rectangle = length×breadth
600 = l× 25
600/25 = length
24 cm = length
now ,
perimeter of rectangle= 2(l+b)
= 2( 24+25)
= 2(49).
= 98cm..
thus , perimeter of rectangle is 98 cm.
hope this helps!!!!
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