find the perimeter of a rectangle whose area is 600 cm sq. and breath is 25 cm.
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Answered by
7
Area of rectangle = lxb
600 = l x 25
l = 24 cm
Perimeter of rectangle = 2(l+b)
= 2x(24+25)
= 2x(49)
=98 cm...
I hope it will help u....
600 = l x 25
l = 24 cm
Perimeter of rectangle = 2(l+b)
= 2x(24+25)
= 2x(49)
=98 cm...
I hope it will help u....
Answered by
2
Answer:
Perimeter of the rectangle is 98 cm
Step-by-step explanation:
It is given that the area of the rectangle is 600 cm^2 and breadth of the rectangle is 25 cm.
And, from the properties of rectangle we know that area of rectangle remains equal to the product of its length and breadth.
Thus,
= > 600 cm^2 = 25 cm x length
= > 600 m^2 =25 cm x length
= > 600 m^2 / 25 m = length
= > 24 m = length
Therefore,
Perimeter of the rectangle = 2( length + breadth )
= 2( 24 cm + 25 cm )
= 2 ( 49 cm )
= 98 cm
Hence,
Perimeter of the rectangle is 98 cm.
Perimeter of the rectangle is 98 cm
Step-by-step explanation:
It is given that the area of the rectangle is 600 cm^2 and breadth of the rectangle is 25 cm.
And, from the properties of rectangle we know that area of rectangle remains equal to the product of its length and breadth.
Thus,
= > 600 cm^2 = 25 cm x length
= > 600 m^2 =25 cm x length
= > 600 m^2 / 25 m = length
= > 24 m = length
Therefore,
Perimeter of the rectangle = 2( length + breadth )
= 2( 24 cm + 25 cm )
= 2 ( 49 cm )
= 98 cm
Hence,
Perimeter of the rectangle is 98 cm.
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