Question

Find the perimeter of a rectangle whose area is 650 m' and its breadth is 13m.
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Answer 1

Answer:

Area of the rectangle =650 cm

2

Breadth =13 cm

Length = Area / breadth

=650/13

=50 cm

Perimeter =2(length +breadth)

=2(50+13) cm

=2(63)

=126 cm

Answer 2

Given :-

• Area of the rectangle = 650m²
• Breadth = 13m

To find :-

Perimeter of rectangle

To find the perimeter of the rectangle we first have to find the length of rectangle.

Let us assume length to be x

Area = Length × Breadth

Hence by substituting the values,

650 = x × 13

By transposing 13 to the LHS (Left Hand Side),

$\dfrac{650}{13} = x$

$50 = x$

Now that we know the length of the rectangle let us find the perimeter of the rectangle.

Perimeter of a rectangle = 2(length+breadth)

Substituting the values,

Perimeter = 2(50+13)

=≥ 2(63)

=≥ 126m

Therefore the perimeter of the rectangle is 126m

More to know :-

Perimeter of square = 4 × side

Area of square = (side)²

Perimeter of a parallelogram = 2(base+height)

Area of a parallelogram = base × height

Perimeter of rhombus = 4 × side

Area of the rhombus = ½ × Diagonal 1 × Diagonal 2

Perimeter of a trapezium = Sum of it's sides

Area of the trapezium = ½ × height × (sum of parallel sides)

Perimeter of a triangle = sum of its sides

Area of a triangle = ½ × base × height