Question

Find the perimeter of a rectangle whose breadth is 10cm and diagonal is 26 cm​

Answer 1

Answer:

$\underline{\bigstar{\sf\ Given :}}$

• Breadth of rectangle= 10 cm
• Diagonal of rectangle = 26 cm

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$\underline{\bigstar{\sf\ To\:Find:}}$

• Perimeter of the rectangle

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$\underline{\bigstar{\sf\ Solution :}}$

Since, the ACB = 90°

→ So, by using Pythagoras Theorem,

AC² + CD² = AD²

CD² = (26) ² - (10) ²

CD²= 676 - 100

CD² = 576

CD = √576

CD = 24

Therefore,

Length of rectangle = 24 cm

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→ Perimeter of rectangle = 2 (L + B)

= 2 (24 + 10)

= 2 (34)

= 68 cm

Answer 2

Answer:

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