Question

) Find the perimeter of a rectangle whose length is 20 c.m and a diagonal is 25 c.m​

Answer 1

Answer:

Length of rectangle = 20cm (l)

diagonal of rectangle = 25cm (d)

Step-by-step explanation:

On using Baudhayan Theorum,

l^2 + b^2 = d^2,

where,

l - length of rectangle

b - breadth of rectangle

d - diagonal of rectangle

Therefore,

=> (20cm)^2 + b^2 = (25cm)^2

=> 400 sq. cm + b^2 = 625 sq. cm

=> b^2 = ( 625 - 400 )sq.cm

=> b^2 = 225 sq. cm

=> b = Square root of 225 sq.cm

=> b = 15cm

Thereby,

Perimeter of rectangle = 2(l+b)

=> 2 × ( 20cm + 15cm )

=> 2 × 35cm

=> 70cm

Hence,

Perimeter of rectangle is 70cm.

Answer 2

Answer:

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