Question

Find the perimeter of a rectangle whose length is 4 times its breadth and its area is 23726 sq.cm.

Answer 1

Hello...
Given: area =23726 sq.cm
solution: let the breadth be x
then length of rectangle is 4x.
Area of rectangle= length ×breadth
23726. = 4x × x
23726= 4x^2
23726÷4 = x^2
59315.5= x^2
$\sqrt{5} 59315.5 = x$
and then u can find the square root and then u find perimeter
hopes it will help u
thanks
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