find the perimeter of a rectangle whose length is 40 cm and a diagonal is 41 cm.
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diagnol = root(l^2 + b^2)
l=40, diagnol=41
41= root(40^2 + b^2)
41= root(1600+b^2)
square on both sides
41^2 = 1600+b^2
1681= 1600 +b^2
b^2= 1681-1600
b^2=81
b=9
l=40,b=9
perimeter = 2(l+b)
= 2(40+9)
=2(49)
=98 is perimeter of rectangle is answer
l=40, diagnol=41
41= root(40^2 + b^2)
41= root(1600+b^2)
square on both sides
41^2 = 1600+b^2
1681= 1600 +b^2
b^2= 1681-1600
b^2=81
b=9
l=40,b=9
perimeter = 2(l+b)
= 2(40+9)
=2(49)
=98 is perimeter of rectangle is answer
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