find the perimeter of a rectangle whose length is 40 cm and a diagonal is 41 CM
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given that length=40 cm diagonal length = 41 cm
The diagonal of the rectangle divides it into two right-angled triangles, so we can use the pythagorean theorem to solve this problem.
41cm is the diagonal and 40cm is the length.
hyp² = length² + breadth²
41² = 40² + breadth²
1681 = 1600 + breadth²
1681 - 1600 = breadth²
breadth² = 81
breadth = √81
= 9cm
Perimeter = 2( l + b )
= 2 * (40 + 9)
= 2 * 49
= 98cm
The perimeter of the rectangle is 98cm.
I hope it is helped you
The diagonal of the rectangle divides it into two right-angled triangles, so we can use the pythagorean theorem to solve this problem.
41cm is the diagonal and 40cm is the length.
hyp² = length² + breadth²
41² = 40² + breadth²
1681 = 1600 + breadth²
1681 - 1600 = breadth²
breadth² = 81
breadth = √81
= 9cm
Perimeter = 2( l + b )
= 2 * (40 + 9)
= 2 * 49
= 98cm
The perimeter of the rectangle is 98cm.
I hope it is helped you
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