Question

Find the perimeter of a rectangle whose width is 5 cm and diagonal is 13cm

Answer 1

Width of the rectangle =5cm (BC)

Diagonal length =13cm (AC)

Let rectangle be ABCD and diagonal be AC

Length of the rectangle =?(AB)

Perimeter of the rectangle =?

Angle B=90

So by Pythagoras property

(AB)^2+(BC)^2=(AC)^2

(AB)^2+5^2=13^2

(AB)^2=169-25=144

AB=12cm

Perimeter of the rectangle =2 ×(l+b)

=2×(12+5)

=2×17

= 34cm

I hope it will help you ☺