Question

Find the perimeter of a rectangular park if its length200 metre and area is 4800.Find the cost of levelling the park at the rate of ₹ 1.35 per m

Answer 1

Answer:

length: 200

area: 4800

breadth: X

area of rectangle: lxb

Xx200= 4800

X=4800/200

X=24

breadth: 24

Perimeter:

2(l+b)

2(24+200)

2(224)

=448

so, perimeter is 448

cost of leveling one m= 1.35

so cost of leveling 448m = 448*1.35

= rupees 604.8

Answer 2

Answer:

Perimeter of Rectangle = 2(l+b)

4800 = 2(200 + b)

4800/2 = 200 + b

2400-200 = b

2200 = breadth

Cost of levelling the park = Area * 1.35

= 4800 * 1.35

= 6480