Find the Perimeter of a rhombus in which diagonals are 6cm and 8cm. (Hint: Find the side of rhombus by using Pythagoras theorem in one of the four triangles formed by diagonals).
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Diagonal 1 = 6 cm
Diagonal 2 = 8cm
Lets find side of rhombus
First divide the rhombus in four triangles
Second take a triangle and use pythagoras theorem to find side
Let the side be X
So X square = Half of diagonal 1 square + Half of diagonal 2 square
X square = 3 square + 4 square
X square = 9+ 16
X square = 25
X = root under 25
X = 5 cm
So the perimeter of the rhombus will be 4* side
= 4*5
=20 cm
I hope It helped you
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Answer:
the answers is Perimeter = 20 cm and 6m Respectively
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