Math, asked by Nandani02, 1 year ago

Find the Perimeter of a rhombus in which diagonals are 6cm and 8cm. (Hint: Find the side of rhombus by using Pythagoras theorem in one of the four triangles formed by diagonals).

Answers

Answered by Piyush362
18

Diagonal 1 = 6 cm


Diagonal 2 = 8cm


Lets find side of rhombus


First divide the rhombus in four triangles


Second take a triangle and use pythagoras theorem to find side


Let the side be X


So X square = Half of diagonal 1 square + Half of diagonal 2 square


 X square = 3 square + 4 square


X square = 9+ 16


X square = 25


X = root under 25


X = 5 cm




So the perimeter of the rhombus will be 4* side


                                        = 4*5


                                        =20 cm





I hope It helped you



Answered by ranjubsg
2

Answer:

the answers is Perimeter = 20 cm and 6m Respectively

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