Question

find the perimeter of a rhombus, length of whose diagonals are 16cm and 12cm.

Answer 1

area of rhombus=1/2*base*height

area of rhombus=1/2*16*12=8*12=96 cm^2 is answer

Answer 2

$side = \frac{1}{2 } \sqrt{ {d1 }^{2} + {d2}^{2} } \\ = \frac{1}{2} \sqrt{ {16}^{2} + {12}^{2} } \\ = 10 \\p erimeter = 4 \times side \\ = 4 \times 10 \\ = 40cm$