Find the perimeter of a rhombus , the lengths of whose diagonals are 16 cm and 30 cm
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First sketch. Figure of Rhombus
Than connect its Diagonals
Diagonals of a Rhombus bisect as per the property
Now four triangles are formed
Since the diagonals bisect which means two lengths are 8cm and 15cm of one of the four triangles
Another property of Rhombus is that their Diagonals bisect at Right angles
Which means that we can apply Pythagoreans theorem to evaluate the value of a side
(Side)²=(8)²+(15)²
Hence Side=17cm(Pythagoreans triplet)
One more property of Rhombus states that all the sides are equal in length of a rhombus meaning that all the four sides are of 17cm
Perimeter of a Rhombus is the sum of its sides since its the boundary
Perimeter=4*side=4*17cm=68cm
Than connect its Diagonals
Diagonals of a Rhombus bisect as per the property
Now four triangles are formed
Since the diagonals bisect which means two lengths are 8cm and 15cm of one of the four triangles
Another property of Rhombus is that their Diagonals bisect at Right angles
Which means that we can apply Pythagoreans theorem to evaluate the value of a side
(Side)²=(8)²+(15)²
Hence Side=17cm(Pythagoreans triplet)
One more property of Rhombus states that all the sides are equal in length of a rhombus meaning that all the four sides are of 17cm
Perimeter of a Rhombus is the sum of its sides since its the boundary
Perimeter=4*side=4*17cm=68cm
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