Find the perimeter of a rhombus whose diagonals are 16cm and 12cm
Answers
Answered by
3
Answer:
Given:
Diagonal,d1 = 16 cm
Diagonal,d2 = 12 cm
To find out:
Find the perimeter of a rhombus ?
Solution:
We know, Diagonal of rhombus bisect each other at right angles.
AC = 16 cm, OC = 1/2 AC ⇒ 1/2 × 16 = 8 cm
BD = 12 cm, OD = 1/2 BD ⇒ 1/2 × 12 = 6 cm
By using pythagoras therome
DC² = OC² + OD²
DC² = 8² + 6²
DC² = 64 + 36
DC² = 100
DC = 10 cm
Therefore,
DC = BC = AD = AB = 10 cm [ All sides are equal ]
Now,
perimeter of rhombus = 4 ( Side )
= 4 × 10
= 40 cm
Answered by
2
Step-by-step explanation:
Q.
Find the perimeter of a rhombus whose diagonals are 16 cm and 12 cm
.
Solution -
Given -
Diagonal 1 (p) = 16 cm
Diagonal 2 (q) = 12 cm
.
Hence perimeter = 40 cm.
hope it helps.
Similar questions