find the perimeter of a rhombus whose one diagonal is 16 CM
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Given
Diagonal of rhombus ( d ) = 16cm
Perimeter of rhombus ( p ) = 2 √ p2 + q2
( p ) = 2 √ ( 16 ) 2 + ( 16 ) 2
( p ) = 2 √ 256 + 256
( p ) = 2 √ 512
( p ) = 45.25cm
Diagonal of rhombus ( d ) = 16cm
Perimeter of rhombus ( p ) = 2 √ p2 + q2
( p ) = 2 √ ( 16 ) 2 + ( 16 ) 2
( p ) = 2 √ 256 + 256
( p ) = 2 √ 512
( p ) = 45.25cm
aashutosh68:
no its wrong answer 40 aayega
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