find the perimeter of a rhombus with diagonal 30 cm and 40 cm long
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Step-by-step explanation:
Let,
BD=30cm
AC=40cm
Let the middle point be O
So,
AO=20 cm and BO=15 cm
Using Pythagoras Theorem
(AB)
2
=(AO)
2
+(BO)
2
⇒(AB)
2
=20
2
+15
2
⇒(AB)
2
=400+225
⇒(AB)
2
=625cm
⇒AB=25cm
∵All sides of rhombus are equal so
Perimeter of a rhombus = 4×(side)
=4×25
= 100 cm
∴Perimeter of a rhombus is 100 cm
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