find the perimeter of a rhombus with diagonals 30 and 40
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perimeter of rohmbus - 1/2(d1)(d2) - 600
bhavitha1135:
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Diagonal 30cm = 15cm+15cm (Lengths of right triangle within rhombus)
Diagonal 40cm = 20cm+20cm (Lengths of right triangle within rhombus)
we have to find the side of rhombus using Pythagoras theorem,
Formula to find perimeter,
p = 4s
s = side of rhombus,
15^2 + 20^2 = s^2
225 + 400 = s^2
625 = s^2
s = 25
Now perimeter of rhombus,
= 4*s
= 4*25
= 100
Therefore result of perimeter is 100cm
Diagonal 40cm = 20cm+20cm (Lengths of right triangle within rhombus)
we have to find the side of rhombus using Pythagoras theorem,
Formula to find perimeter,
p = 4s
s = side of rhombus,
15^2 + 20^2 = s^2
225 + 400 = s^2
625 = s^2
s = 25
Now perimeter of rhombus,
= 4*s
= 4*25
= 100
Therefore result of perimeter is 100cm
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