find the perimeter of a rhombus with diagonals 30 cm and 40 cm long
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The diagonals of a rhombus are perpendicular bisectors of each other.
The sides of a rhombus are equal in measures.
30/2 = 15 , 40/2 = 20 bisectors of diagonals
Side of the rhombus becomes hypotenuse.
(Side)^2 =(15)^2+( 20)^2 (Pythagoras Theorem)
(Side)^2= 225 + 400
(Side)^2 = 625
Side = 25 (taking square root)
Perimeter = 4*side = 4*25 =100 cm
Ans : 100 cm
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