Question

find the perimeter of a square if it's diagonal is 10√2 cm?​

Answer 1

Answer:

P=22d=2·2·10≈28.28427

Step-by-step explanation:

Answer 2

Answer:

40 cm

Using Pythagoras theorem

let side be AB , BC, CD, DA of the square

(AB)² + (BC)² = (10√2)²

X² + ² = 200

2X² = 200

X² = 200/2

X = √100

X = 10

Perimeter = 4 × side

4× 10

40