Question

Find the perimeter of a square whose area is 121 square feet

Answer 1

Area of square = S × S = S^2
Side of square = √S^2
Area of square = 121 ft.^2
Thus, side = √121 = 11

Perimeter of square = 4 × s
Perimeter of square = 4 × 11 = 44 feet.

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Answer 2

Let the side be x ( because all Side of the square is equal
area of square is ( side² )
then, x² = 121
x = √121
x = 11
So , perimeter of square is 4 × side
4 × 11
44
44 is perimeter of the square
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