Question

find the perimeter of a square whose area is 841cm²​

Answer 1

Question

find the perimeter of a square whose area is 841cm²

Given that

• Area of square=841cm²

Find perimeter of Square=?

Area of square=(side)²

(side)²= 841cm²

side= √841cm

side= √29×29cm

side= 29 cm

perimeter of Square= 4×side

perimeter of Square= 4×29

perimeter of Square=116 cm

For more information

Perimeter of Rectangle = 2(l+b)

Area of Rectangle= length× breadth

Area of Rohmbus= (d1×d2)/2

Area of Trapezium= 1/2(sum of parallel sides)×h

Answer 2

$\sf \pmb{Answer :}$

Question

find the perimeter of a square whose area is 841cm²

Given that

Area of square=841cm²

Find perimeter of Square=?

Area of square=(side)²

(side)²= 841cm²

side= √841cm

side= √29×29cm

side= 29 cm

perimeter of Square= 4×side

perimeter of Square= 4×29

perimeter of Square=116 cm

For more information

Perimeter of Rectangle = 2(l+b)

Area of Rectangle= length× breadth

Area of Rohmbus= (d1×d2)/2

Area of Trapezium= 1/2(sum of parallel sides)×h