Question

find the perimeter of a triangle whose side are in the ratio 3:4:5 and the longest side is 15​

Answer 1

Sides are in the ratio 3:4:5

Longest side is 15

Thus the common multiple must be 3

(as 5x3=15)

Sides are 9,12,15

Perimeter=9+12+15=36 units

Answer 2

Answer:

• 3+4+5=12 eqn1

Step-by-step explanation:

Longest side = 15

So 5×3=15

Multiply other terms

5×4=20

5×5=25=60 eqn 2

Now 60÷12=5

So the sides are 3cm,4cm and 5cm.

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