Find the perimeter of a triangle whose sides are 2y+3z,z-y,4y-2z
Answers
Answered by
26
side of the triangle
2y+3z,z-y,4y-2z
perimeter of a triangle = sum of it's all sides.
= 2y+3z+z-y+4y-2z
= 5y+ 2z units.
2y+3z,z-y,4y-2z
perimeter of a triangle = sum of it's all sides.
= 2y+3z+z-y+4y-2z
= 5y+ 2z units.
Answered by
96
Hi ,
2y + 3z , z - y , 4y - 2z are three sides of the
Triangle .
Perimeter = sum of the three sides
= 2y + 3z + z - y + 4y -2z
= 2y - y + 4y + 3z + z - 2z
= 5y + 2z
I hope this helps you.
: )
2y + 3z , z - y , 4y - 2z are three sides of the
Triangle .
Perimeter = sum of the three sides
= 2y + 3z + z - y + 4y -2z
= 2y - y + 4y + 3z + z - 2z
= 5y + 2z
I hope this helps you.
: )
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