Find the perimeter of a triangle whose vertices have the (3,10) (5,2) (4,12)
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Let , the vertices of triangle be A(3,10) , B(5,2) and C(4,12)
The distance between point A(3,10) and B (5,2) is
The distance between the point B(5,2) and C(4,12) is
The distance between A(3,10) and C(4,12) is
Therefore , the perimeter of triangle whose vertices are A(3,10) , B(5,2) and C(4,12) is
Hence , the perimeter of triangle is 20.53 units
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