Find the perimeter of a triangle with vertices (0,4),(0,0)and(3,0)
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Perimeter of triangle ABC = AB + BC + AC
To find AB, BC, AC use distance formula
To find AB, BC, AC use distance formula
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perimeter of the circle = sum of all sides=ab+BC+ac. firstly coordinates are a(0,4) ,b(0,0) and c(3,0) so, ab = √(x2-x1)²+(y2-y1)²= √(0)²+(-4)²= √16= 4units BC=√(3)²+(0)² = √9 = 3units ac= √(3)²+(-4)² = √9+16= √25= 5 units. therefore perimeter= 4+3+5= 12 units. hence found.
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