Question

Find the perimeter of parallelogram whose adjacent sides are 5 1/2 cm and 3 2/3​

Answer 1

Answer:

easy do 2 × sum of adjacent sides

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Answer 2

$\underline{\underline{\huge{\gray{\tt{\textbf Answer :-}}}}}$

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$\sf\large\bold{\orange{\underline{\blue{ Given :-}}}}$

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• One side of parallelogram is $\sf 5 \dfrac { 1 } { 2 }$ cm.

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• Other adjacent side is $\sf 3 \dfrac { 2 } { 3 }$ cm.

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$\sf\large\bold{\orange{\underline{\blue{ To \: Find :-}}}}$

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• Perimeter of parallelogram

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$\sf\large\bold{\orange{\underline{\blue{ Solution :-}}}}$

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$\underline{\bold{\texttt{Perimeter of parallelogram :}}}$

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➠ 2(l + b) ⚊⚊⚊⚊ ⓵

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Where ,

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• l = Length

• b = Breadth

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We know that in a parallelogram length and breadth are adjacent to each other

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Thus , let the length be $\sf 5 \dfrac { 1 } { 2 }$ & the breadth be $\sf 3 \dfrac { 2 } { 3 }$

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$\underline{\bold{\texttt{Perimeter of given parallelogram :}}}$

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• l = $\sf 5 \dfrac { 1 } { 2 }$

• b = $\sf 3 \dfrac { 2 } { 3 }$

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⟮ Putting the above values in ⓵ ⟯

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➜ 2(l + b)

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➜ $\sf 2(5 \dfrac { 1 } { 2 } + 3 \dfrac { 2 } { 3 } )$

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➜ $\sf 2( \dfrac { 11 } { 2 } + \dfrac { 11 } { 3 } )$

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➜ $\sf 2( \dfrac { 33 + 22} { 6 })$

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➜ $\sf 2( \dfrac { 55} { 6 })$

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➨ $\sf \dfrac { 55} { 3 }$ cm.

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• Hence the perimeter of parallelogram is $\sf \dfrac { 55 } { 3 }$ cm.