Question

find the perimeter of ractangle whose lengthis16.cm and breath is 8cm.​

Answer 1

Answer:

2 x ( 16 + 8 )

2 x 24

48 cm is the answer.

Answer 2

Explanation:

Question :-

• Find the perimeter of rectangle whose length is 16 cm and breadth is 8 cm.

To Find :-

• Perimeter of rectangle.

Solution :-

Given :

• Length = 16 cm
• Breadth = 8 cm

By using the formula,

${\sf{\longrightarrow Perimeter\ of\ rectangle\ =\ 2(l\ +\ b)}}$

Where,

• l = length
• b = breadth

According to the question, by using the formula, we get :

${\sf{\longrightarrow Perimeter\ of\ rectangle\ =\ 2(l\ +\ b)}}$

${\sf{\longrightarrow 2(16\ +\ 8)}}$

${\sf{\longrightarrow 2(24)}}$

${\sf{\longrightarrow 2 \times 24}}$

${\sf{\longrightarrow 48\ cm}}$

$\therefore$ Hence, perimeter of rectangle is 48 cm.

More To Know :-

$\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}$