Question

Find the perimeter of rectangle field whose length four times its width and which has equal to 30976

Answer 1

$\huge\underline\mathfrak{Answer:-}$

Perimeter of Rectangle= 880unit



$\huge\underline\mathfrak{Solution:-}$



$\textbf{Formula used}$

Area of Rectangle= l×b

Perimeter of Rectangle=2(l+b)



$\bf\underline{Step -by -Step -solution}$

$\bold\underline {According to given condition}$

Let breathe of Rectangle= x

$\textbf{so,}$ Length= 4x

$\textbf{Step .1}$

Area of Rectangle=30976

$\textbf{Therefore}$

l×b=30976

$\textbf{Step 2}$

Put value of $\textbf{Length}$and $\textbf{Breadth}$

$(x) \times (4x) = 30976$

$\textbf{Step 3}$

$4 {x}^{2} = 30976$

$\textbf{Step 4}$

${x}^{2} = \frac{30976}{4}$

$\textbf{Step 5}$

${x}^{2} = 7744$

$\textbf{Step 6}$

$x = \sqrt{7744}$

$\textbf{Step 6}$

$x = 88unit$



$\textbf{ Hence}$

Length of Rectangle= 88 unit

Breadth of Rectangle= 4x

= 4×88

= 352

$\textbf{So, Perimeter}[/$

2(l+b)

=2(88+352)

=880 units

Answer 2

$\huge\boxed {Answer:-}$

Let the breadth be $x$

Length = $4y$

$\boxed{Area}$ $= l \times b$

$lb = 30976$

$4y \times y = 30976$

$4 {y}^{2} = 30976$

${y}^{2} = \frac{30976}{4}$

$y = \sqrt{7744}$

$y = 88m$

Now,

$\boxed{Length}$

$= 4y$

$= 4 \times 88$

$= 352m$

$\boxed{Perimeter}$

$= 2 (l + b)$

$= 2(88 + 352)$

$= 2 \times 440$

$= 880m$

Therefore,

The perimeter of the rectangle is $880m.$

$\huge {Be\:Brainly}$❤️