Question

find the perimeter of rectangle if area is 440 metre square and length is 44 CM ​

Answer 1

Answer:

area of rectangle = 440 m sq.

length of rectangle = 44 cm = 0.44m

area of rectangle = length × breath

440 = 0.44 × breath

440/0.44 = breath

breath = 100 m

perimeter of reactangle = 2(length + breath)

= 2(0.44+100)

= 2(100.44)

200.88 m

Answer 2

$\huge {\orange{ \underline{ \overline{ \boxed{ \mathbb{ \blue{ANSWER}}}}}}}$

$\sf{ \green{\underline{ \underline{GIVEN :}}}}$

• Area of rectangle = 440 $\sf {m}^{2} \: or \: </strong><strong>44</strong><strong>,</strong><strong>00</strong><strong>,</strong><strong>000</strong><strong>{cm}^{2}$
• Length = 44 cm.

$\sf{ \green{\underline{ \underline{TO\: FIND:}}}}$

• Perimeter of the rectangle.

$\sf{ \green{\underline{ \underline{SOLUTION :}}}}$

As we need breadth to find out the perimeter. So let us first find out the breadth of the rectangle.

We know,

$\boxed{\sf \red{Area \: of \: rectangle \: = \: length(l) \: \times \: Breadth(b)}}$

$\implies \: \sf 44,00,000 = 44 × b$

$\implies \: \sf \: b = \frac{44,00,000}{44}$

$\boxed{\therefore \: \sf \: b \: = 1,00,000 \: cm}$

Now,

$\boxed{\sf \red{Perimeter \: of \: rectangle(P) \: = \: 2(length \: + \: Breadth)}}$

$\sf{ \implies \: P \: = 2( \: 44 \: + \: 100000)}$

$\sf{ \implies \: P \: = 2 \: \times \: 100044 }$

$\boxed{\sf{ \therefore \: P \: = \: 200088 \: cm \: or \: 2000.88 \: m}}$

Hence, the required perimeter of the rectangle is 2000.88 m.

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