Question

find the perimeter of rectangle whose area is 56

Answer 1

Hi Neelam

This should be the answer to your question.

As per the question ,
Area of rectangle , that is 
Length × Breadth = 56
Let us assume length to be represented as 'l' and breadth as 'b'.
So our first equation is 
L × b = 56 
So we get 
L = 56 / b ( transpose )

Now perimeter of rectangle as we know is 
2 ( l + b )
Now simply substitute l in terms of b , we get 
2 ( 56 / b + b )
2 ( 56 + b ² / b )
(112 × b) + (2 × b²) / b

So the perimeter will be 
112 b + 2 b² / b. (There would be a perfect value if at least one of the value , breadth or length is given)

Answer 2

Hlo dear,
here is your answer,

let the lendth of the rectangle = l
breadth = b
area of the rectangle = 56

=> l × b = 56

=> b = 56/l

So we found that b = 56/ l

we know the perimeter of the rectangle

= 2 ( l+b )

= 2 ( l + 56/ l )

= 2 [( l² + 56 ) / l]

= ( 2l² + 112 ) / l


Hope this helps

if u have any doubt or want any help ask me frankly. i would like to help.


Thank you


#Sneha