Question

find the perimeter of rectangle whose b) l=10,b=9​

Answer 1

Perimeter of a rectangle = 2 \times (l + b)

So,

P = 2 × (10+ 9)

P = 2 × (19)

P = 38

Answer 2

$Perimeter \: of \: Rectangle \\ = 2 ( Length + Breadth)$

$= 2(10 + 9)$

$= 2(19)$

$= 2 \times 19$

$= 38 \: m$

$Perimeter \: of \: Rectangle = 38 m$