Question

In quadrilateral ABCD, AP and BP are bisectors of ∠A and ∠B respectively. Find the value of x, if D = 130º, ∠C = 60º.​

Answer 1

solution is given in attachment.

Answer 2

Answer:

AP and BP are bisectors of two adjacent angles A and B of a quadrilateral ABCD.

We know that the sum of all the angles of a quadrilateral is 360°.

⇒∠A+∠B+∠C+∠D=360°, ∠A+∠B=360°−(∠D+∠C)

∴ In △PAB;

⇒∠APB+∠PAB+∠PBA=180° [ Angle sum property ]

⇒∠APB+

2

1

∠A+

2

1

∠B=180°

∴AP and BP are the bisectors of two adjacent angles A and B.

∴2∠APB+∠A+∠B=360°

⇒2∠APB=360°−(∠A+∠B)

∴2∠APB=∠C+∠D

⇒∠APB=

2

130

o

+60

o

=95°

∴x=95°.

Hence, the answer is 95°.