Question

find the perimeter of rectangle whose length is 12 centimetre and diagonal is 18​

Answer 1

Answer:

(24+6 root 2) centimeter

Step-by-step explanation:

length = 12 cm

diagonal = 18 cm

18^2=12^2 + b^2           b=breath

324=144+b^2

324-144=b^2

18=b^2

b=root of 18

perimeter=2(l+b)

2(12+root of 18)=(24+6 root 2) centimeter

Answer 2

Answer:

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$<font color ="purple"><h1>perimeter =?</h1>$

Given:-

length =12cm

diagonal =18cm

by Pythagoras thereom

$18^{2}=12^{2}+b^{2}$

$324=144 +b^{2}$

$b^{2}=324-144$

$b^{2}=180$

$b= square root of 180$

$b=13.41cm$

perimeter =2(L+B) for

2(12+13.41)

2(25.41)

50.82cm Answer