find the perimeter of regular rectangle whose length is 3 times of breadth and area is 900sq cm
Answers
Answered by
0
Answer:
let breadth =x
length=3x
area=900sqcm
area=l*b
900=3x * x
900=3xsquare
900/3= xsquare
300=x square
17.320 square =x square
square cancel square
17.320
Answered by
0
Answer:
Step-by-step explanation:
Let breadth=x
Length will be 3x
Formula = l*b
3x*x = 900cm
3x^2=900
X^2=900/3=300cm
X^2=17.32^2
Powers cutted
So length= 3*17.32=51.96
Perimeter - 2(l+b)
2(51.96+17.32)
2*69.29=138.56cm
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