Question

find the perimeter of regular rectangle whose length is 3 times of breadth and area is 900sq cm​

Answer 1

Answer:

let breadth =x

length=3x

area=900sqcm

area=l*b

900=3x * x

900=3xsquare

900/3= xsquare

300=x square

17.320 square =x square

square cancel square

17.320

Answer 2

Answer:

Step-by-step explanation:

Let breadth=x

Length will be 3x

Formula = l*b

3x*x = 900cm

3x^2=900

X^2=900/3=300cm

X^2=17.32^2

Powers cutted

So length= 3*17.32=51.96

Perimeter - 2(l+b)

2(51.96+17.32)

2*69.29=138.56cm