Question

find the perimeter of square with side 4x² +8y -8​

Answer 1

Step-by-step explanation:

You want zeros of y or what?

if zeros:

4 x^2 - 12 x + 9 = 0

(2 x-3)(2x-3) = 0

x = 1.5, 1.5 double root

If vertex etc:

4 x^2 -12 x = y - 9

x^2 - 3 y = (1/4)(y-9)

x^2 - 3 y + 9/4 = (1/4)y

(x-1.5)^2 = y/4

vertex at (1.5 , 0) which we knew already

Answer 2

Answer:

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Step-by-step explanation:

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