find the perimeter of the following.1)traingle ABC in which AB =9.3cm, BC =7cm and CA =5.1cm 2)square of side 2.6cm 3)regular pentagon of side 3.5cm
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Answered by
2
1) P = sum of three sides
P= 9.3+7+5.1
P =21.4 cm
2) P of square = 4× length of side
P= 4×2.6
P = 10.4 cm
3) P of regular pentagon = 5 × length of side
P = 5 ×3.5
P = 17.5 cm
P= 9.3+7+5.1
P =21.4 cm
2) P of square = 4× length of side
P= 4×2.6
P = 10.4 cm
3) P of regular pentagon = 5 × length of side
P = 5 ×3.5
P = 17.5 cm
Answered by
1
Answer:
iii) 5×3.5
= 15.3
hope it helps you
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