Question

find the perimeter of the following
1. triangle abc in which ab =9.3 cm,bc=7cm and ca=5.1cm
2. square of side 2.6 cm
3. rectangle of length 5 m and breadth 250 cm
4. regular Pentagon of side 3.5 cm​

Answer 1

ANSWER:

• Perimeter of ∆= 21.4cm

• Perimeter of Square=10.4cm

• Perimeter of rectangle=15m

• Perimeter of pantagon=17.5cm

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EXPLANATION:

Here in this question, concept of perimeter is used. We have to find perimeter of different shapes whose dimensions are given.

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Before finding perimeter, we should know first what perimeter actually is!

Perimeter→  The length of the boundary of a given figure is called it's perimeter.

It means we can obtain perimeter by adding the length of all sides of the given figure.

So let's start!

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FOR TRIANGLE:

Given lengths are:-

AB=9.3cm

BC=7cm

AC=5.1cm

Perimeter of triangle=Sum of all sides

Perimeter of triangle=9.3cm+ 7cm+ 5.1cm

Perimeter of triangle=21.4cm

So the perimeter of triangle is 21.4cm

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FOR SQUARE:

Given length:-

Side of square=2.6cm

Perimeter of square=4×Side

Perimeter of square=4×2.6cm

Perimeter of square=10.4cm

So the perimeter of square is 10.4cm

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FOR RECTANGLE:

Given sides:

Length=5m

Breadth=250cm=>250÷100m

=2.5m

Perimeter of rectangle=2(L+B)

Perimeter of rectangle=2(5m+2.5m)

Perimeter of rectangle=2(7.5m)

Perimeter of rectangle=15m

So the perimeter of rectangle is 15m

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FOR REGULAR PANTAGON:

Given side:

3.5cm each

We know that pantagon has 5 sides of equal length.

So let's perimeter can be obtained by following formula:

Perimeter of pantagon=5×Side

Perimeter of pantagon=5×3.5cm

Perimeter of pantagon=17.5cm

So the perimeter of pantagon is 17.5cm

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