Question

Find the perimeter of the following figure. ​

Answer 1

Answer:

Perimeter of triangle= a+b+c

= $3\frac{1}{2} + 4\frac{2}{3} + 5\frac{1}{4}$

= $\frac{7}{2}+\frac{14}{3} +\frac{21}{4}$

LCM of 2,3,4=12

= $\frac{42+56+63}{12}$

=$\frac{161}{12}$