Question

find the perimeter of the following shapes by taking pi 22/7​

Answer 1

Answer:

Perimeter of Quadrant = 57.143mm

Step-by-step explanation:

We Have :-

Quadrant

Radius = 16mm

Angle = 90°

To Find :-

Perimeter

Formula Used :-

$Perimeter\ of\ a\ quadrant= \frac{2\pi r }{4}+2*radius$

Solution :-

$Perimeter = \frac{2 *22*16}{4*7}+2(16)\\ \\= \frac{2*22*4}{7}+32 \\\\= \frac{176}{7} +32\\\\= 25.143+32 mm\\\\=57.143mm$

Perimeter of Quadrant = 57.143mm