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Surface Area of remaining block = TSA of cuboid - 2 (Base Area of Cylinder) + CSA of Cylinder
= 2 (5*10 + 10*15 + 5*15) - 2 (22/7*7/2*7/2) + 2*22/7*7/2*5
= 583 cm2
= 2 (5*10 + 10*15 + 5*15) - 2 (22/7*7/2*7/2) + 2*22/7*7/2*5
= 583 cm2
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Shailesh183816:
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