find the perimeter of the following shapes to 1 Decimal Place. Take π= 3.14.
Please solve Question 9 part 3 and 4
Answers
Figure 1
radius of both circles = 16 cm / 2
= 8 cm
Perimeter of the figure = Circumference of 2 semicircles + 2 Breadth of the rectangles
= 2 × 1 / 2 × 2 π r + 2 × 3 cm
= 2 π r + 6 cm
= 2 × 3.14 × 8 cm + 6 cm
= 50.24 cm + 6 cm
= 56.24 cm
Perimeter is 56.24 cm
Figure 2
Radius of big semi circle = 8 cm/2
= 4 cm
Radius of small semi - circle = 4 cm / 2
= 2 cm
Perimeter = 4 cm + 3 cm + 3 cm + circumference of the small semicircle + circumference of big semi circle.
= 10 cm + 1/2 × 2 π r + 1/2 × 2 π r
= 10 cm + 3.14 × r + 3.14 × r
= 10 cm + 3.14 × 4 + 3.14 × 2
= 10 cm + 12.56 + 6.28
= 28.84
The perimeter is 28.84 cm
Hope it helps ^__^
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radius of both circles = 16 cm / 2
= 8 cm
Perimeter of the figure = ( Circumference of 2 semicircles ) + 2 (Breadth of the rectangles)
=( 2 × 1 / 2 × 2 π r) + (2 × 3) cm
= (2 π r + 6 )cm
=( 2 × 3.14 × 8 + 6) cm
= (50.24 + 6) cm
= 56.24 cm
Perimeter is 56.24 cm
now in figure 2
Radius of big semi circle = 8/2 cm
= 4 cm
Radius of small semi circle = 4 cm / 2
= 2 cm
Perimeter = 4 cm + 3 cm + 3 cm + (circumference of the small semicircle) + (circumference of big semi circle.)
= [10 + ( 1/2 × 2 π r ) + (1/2 × 2 π r) ] cm
= [10 + 3.14 × r + 3.14 × r] cm
= [10 + 3.14 × 4 + 3.14 × 2] cm
= [10 + 12.56 + 6.28] cm
= 28.84 cm
hence, answer is 28.84 cm
HOPE IT HELPS U ✌️✌️✌️