Question

Find the perimeter of the given figure, where AED is a semi-circle and ABCD is a rectangle

Answer 1

$\large \tt AHOY!! \:$

given AED is a semi circle.

we know that opposite sides of a rectangle is equal.

therefore BC = AD = 14cm

the diameter of the semi circle is 14cm.

perimeter of the semi-circle = πr

= 22/7 × 14

= 22 × 2

= 44cm

now, perimeter of the figure = AB + BC + DC + AED

= 20 + 14 + 20 + 44

= 34 + 64

= 98cm

$\large \tt HOPE \: THIS \: HELPS!!$

Answer 2

$\underline {\huge {\underline \red{Answer}}} \\ \\ \green{98cm}$

In the questions Given ,

AED Is a semi circle and ABCD is a rectangle .

The properties of rectangle Opposite sides of rectangle are equal.

Find

The perimeter of the given figure.

Now according to questions,,

Here in rectangle like opposite side are equal BC = AD = 14Cm.

The diameter of semi circle is 14 Cm.

Now we find perimeter of semi circle equal to πr .

$\frac{22}{ \cancel{7}} \times \cancel{ 14} \\ \\ 22 \times 2 \\ \\ 44$

Again we find the perimeter of the given circle .

Sum of all sides of this figure.

AB + BC + CD + AED

20 + 14 + 20 + 44

34 + 64

98 Cm

Therefore the perimeter of the given figure is 98 Cm.

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