Question

find the perimeter of the given question ​

Answer 1

Answer:

mark as brainlist first

Step-by-step explanation:

Let side ofasquare=aunits

Diagonal(d)=12√2units/*given

Now ,

\boxed {Area \: of \the \: square (A)\\=a^{2}=\frac{d^{2}}{2}}

a^{2} = \frac{(12\sqrt{2})^{2}}{2}

\implies a^{2}=\frac{12^{2}\times 2}{2}

\implies a^2 = (12\:unit)^{2}

\implies a = \sqrt{12^{2}}

\implies a = 12\: units

Perimeter \: of \: the \: square (P) = 4r\\=4 \times 12 \:units

\implies P = 48 \: units

Therefore,

Perimeterofthesquare(P)=48units

Answer verified by

Answer 2

GIVEN

Diagonal of square = 12√2

TO FIND

Perimeter

FORMULAE USED

Diagonal of square = side√2

Perimeter of square = 4 × side

SOLUTION

side√2 = Diagonal of square

side√2 = 12√2

√2 cancel out

side = 12

Perimeter = 4 × side

Perimeter = 4 × 12

Perimeter = 48

★ So, the perimeter of square is 48 cm².

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬