Math, asked by shivbhan1981pbqz22, 11 months ago

find the perimeter of the given rectangle (1) length 35 whole 1/2 m and breadth 18 whole 1/2 m​

Answers

Answered by KamaldevSharma
6

Answer:

108 {m}^{2}

Step-by-step explanation:

length = 35 \ \frac{1}{2} =  \frac{71}{2}   \:  \:  \:  \\ breadth =  18 \ \frac{1}{2}  =  \frac{37}{2}  \\ perimeter = 2(length + breadth) \\  = 2( \frac{71}{2}  +  \frac{37}{2} ) = 2 \times  \frac{108}{2 }  = 108 {m}^{2}

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Answered by abhissp4717
0

Answer:

Step-by-step explanation:

Given:

Length=35whole1/2m means 71/2m =35.5m

Breadth or width=18whole1/2m means 37/2m=18.5m

As we know that, perimeter of a rectangle=2(length+breadth/width)

On putting values,we get

2(35.5+18.5)=108m.

Thats all thank you. Have a good day ahead.

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