Question

)Find the perimeter of the rectangle whose area is 11,250sq.mm and

length is 150mm.​

Answer 1

Answer:

450

Step-by-step explanation:

As area and length is given, breadth can be found easily

and if Breadth is found easily, even the perimeter can be found using the formula, and hence, the question is answered

Steps:

Let the breadth be X

Area of the rectangle = L x B

Area of the rectangle = 150 x X

11,250 = 150X

X=11,250/150

X(breadth)=75

Therefore, Breadth of the rectangle = 75

Perimeter of the Rectangle = 2 (L+B) (Formula)

Perimeter of the rectangle = 2 (150+75)

Perimeter of the rectangle = 2 (225)

Perimeter of the rectangle = 2 x 225

Perimeter of the rectangle = 450

and don't forget this following step buddy...

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Answer 2

${ \purple{ \large{ \underline{ \pmb{ \frak{Given : }}}}}}$

★The area of a rectangle is 11250mm²

★ The length of the rectangle is 150mm

${ \purple{ \large{ \underline{ \pmb{ \frak{ To \: Find: }}}}}}$

★ The perimeter of the rectangle

${ \purple{ \large{ \underline{ \pmb{ \frak{Let's \: understand \: the \: concept : }}}}}}$

☀️Concept : Here, as we have been provided with the area of the rectangle and the length of the rectangle let's find the breadth of the rectangle with the given hints

~so, that we can find the perimeter of the rectangle with the dimensions of the rectangle which are the length and the breadth of the rectangle.

${ \purple{ \large{ \underline{ \pmb{ \frak{Using \: concept : }}}}}}$

~ Formula to find the Area of a rectangle is

✪ Area = Length × breadth

~ Formula to find the perimeter of a rectangle is

✪Perimeter = 2( Length + Breadth)

${ \purple{ \large{ \underline{ \pmb{ \frak{ Solution : }}}}}}$

★ The perimeter of the rectangle is 450mm

${ \purple{ \large{ \underline{ \pmb{ \frak{Full \: solution : }}}}}}$

~ As we know that the area of the rectangle is 11250mm² and the length of the rectangle is 150mm so, let's firstly find the breadth of the rectangle

✪ Formula :

~ Area of the rectangle is its Length times its Breadth

${ : \implies} \sf \: Area \: of \: the \: rectangle = l \times b$

${ : \implies} \sf \: 11250 {mm}^{2} =150 \times breadth$

${ : \implies} \sf \: breadth = \dfrac{11250}{150}$

${ : \implies} \sf \: breadth = { \purple{ \underline{ \boxed{ \pmb{ \frak{75mm}}}} \bigstar}}$

• Henceforth the breadth of the rectangle is 75mm

~ Now, let's find the perimeter of the rectangle rectangle using the formula mentioned below Substituting the dimensions of length and breadth with the values which are 150mm and 75mm respectively.

✪ Formula :

~ Perimeter = 2( Length + Breadth )

${ : \implies} \sf \: Perimeter \: of \: the \: rectangle = 2(l + b)$

${ : \implies} \sf \: Perimeter \: of \: the \: rectangle = 2(150mm + 75mm)$

${ : \implies} \sf \: Perimeter \: of \: the \: rectangle = 2(225mm)$

${ : \implies} \sf \: Perimeter \: of \: the \: rectangle = { \purple{ \underline{ \boxed{ \pmb{ \frak{450mm}}}} \bigstar}}$

• Henceforth the perimeter of the rectangle is 450mm

${ \purple{ \large{ \underline{ \pmb{ \frak{ Additional \: Information : }}}}}}$

★ Area of a Rhombus = ½ × D1 × D2

★ Area of a Square = Side × Side

★ Area of a Parallelogram = Base × Hieght

★ Area of a Triangle = ½ × Base × Height

★ Area of a Circle = πr²

★ Perimeter of a Square = 4 × Side

★ Perimeter of a Parallelogram = 2( a + b )

★ Perimeter of a Circle = 2πr

★ Perimeter of a Triangle = Sum of all sides

${ \purple{ \large{ \underline{ \pmb{ \frak{Diagram : }}}}}}$

❍ Rectangle :

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 150 mm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 75 mm}\end{picture}$

[ Note: Kindly view the diagram from the website]