Question

find the perimeter of the rectangle whose breadth is 95.5 m and its length is double of the breadth​

Answer 1

At first

breadth=95.5

length=2*95.5 =191

perimeter = 2(l + b)

= 2(191+95.5)

=2*286.5

=573m²

Answer 2

Question :-

find the perimeter of the rectangle whose breadth is 95.5 m and its length is double the breadth.

Required Answer :-

Given :- Breadth of rectangle = 95.5 m

According to the condition,

Length = 2 x breadth

Length = 2 x 95.5

Length = 191 m

Perimeter of rectangle = 2(l + b)

= 2(191 + 95.5)

=2(286.5)

= 573 m

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