Find the perimeter of the rectangle whose dimensions are zero values of quadratic polynomial x2+7x+12
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hey..
x^2 + 7x + 12 = 0
x^2 + 3x + 4x + 12 = 0
x(x + 3) + 4(x + 3) = 0
(x + 4)(x + 3) = 0
x = -4 and x = -3
perimeter of rectangle = 2(l + b)
= 2(-4-3)
= 2(-7)
= -14
x^2 + 7x + 12 = 0
x^2 + 3x + 4x + 12 = 0
x(x + 3) + 4(x + 3) = 0
(x + 4)(x + 3) = 0
x = -4 and x = -3
perimeter of rectangle = 2(l + b)
= 2(-4-3)
= 2(-7)
= -14
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